x^2+16x=-62

Solution for x^2+16x=-62 equation:

x^2+16x=-62

We move all terms to the left:

x^2+16x-(-62)=0

We add all the numbers together, and all the variables

x^2+16x+62=0

a = 1; b = 16; c = +62;
Δ = b2-4ac
Δ = 162-4·1·62
Δ = 8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{8}=\sqrt{4*2}=\sqrt{4}*\sqrt{2}=2\sqrt{2}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(16)-2\sqrt{2}}{2*1}=\frac{-16-2\sqrt{2}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(16)+2\sqrt{2}}{2*1}=\frac{-16+2\sqrt{2}}{2}
$